Java program on Manual Exceptions with 'throw' keyword
In Java, a programmer can throw exceptions manually using 'throw' keyword.
50
Enter value of num2
70
Exception caught
Mistake in subtraction
PROGRAM:
import java.util.Scanner;
public class ManualException {
public static void main(String[] args) {
int num1, num2, result;
Scanner sc = new Scanner(System.in);
System.out.println("Enter value of num1");
num1 = sc.nextInt();
System.out.println("Enter value of num2");
num2 = sc.nextInt();
try {
if (num1 >= num2) {
result = num1 - num2;
System.out.println(result);
} else {
throw new Exception("Mistake in subtraction");
}
} catch (Exception e) {
System.out.println("Exception caught\n" + e.getMessage());
}
}
}
public class ManualException {
public static void main(String[] args) {
int num1, num2, result;
Scanner sc = new Scanner(System.in);
System.out.println("Enter value of num1");
num1 = sc.nextInt();
System.out.println("Enter value of num2");
num2 = sc.nextInt();
try {
if (num1 >= num2) {
result = num1 - num2;
System.out.println(result);
} else {
throw new Exception("Mistake in subtraction");
}
} catch (Exception e) {
System.out.println("Exception caught\n" + e.getMessage());
}
}
}
OUTPUT:
Enter value of num150
Enter value of num2
70
Exception caught
Mistake in subtraction